= [3(x-3) + 2(x+2)] / [(x + 2) (x – 3)]
= (3x - 9 + 2x + 4) / (x² – x – 6)
= (5x – 5) / (x² – x – 6)
Soal nomor 3
4/x + 3 – 5/x – 1
= [4 (x – 1) – 5(x + 3)] / [(x + 3) (x – 1)]
= (4x – 4 – 5x – 15) / (x2 – x + 3x – 3)
= (-x – 19) / (x2 + 2x – 3)
BERITA REKOMENDASI
Soal nomor 4
2a/3x × 2x – 6xy/12a
= 2a/3x × 2x (1 – 3y)/12a6 3
= 1–3y / 9
Soal nomor 5
12/(x – 3) (x + 3) ÷ 3/x+3