Jawab: 2

Pembahasan: ((xⁿ⁻¹ yⁿ)³)/(x²ⁿ y⁶⁺ⁿ)
= (x³ⁿ⁻³ y³ⁿ)/(x²ⁿ y⁶⁺ⁿ)
= x³ⁿ⁻³⁻²ⁿ y³ⁿ⁻⁶⁻ⁿ
= xⁿ⁻³ y²ⁿ⁻⁶
maka,
xⁿ⁻³ y²ⁿ⁻⁶ = xᵃyᵇ
a = n-3 dan b = 2n-6
Nilai b/a =
b/a = (2n-6)/(n-3)
b/a = (2(n-3))/(n-3)
b/a = 2

Soal nomor 4

a. y³ × (3y)²
= y³ × 3² × y²
= 9 × y³⁺²
= 9 y⁵

b. b 2y⁵ × b³ 6 y²
= b¹⸍² . 2 y⁵ × b³ . 6 y²
= b¹⸍²⁺³. 12 . y⁵⁺²
= b⁷⸍² . 12 . y⁷
= b⁷⸍² 12 y⁷

c. (tn³)⁴ × 4t³
= t⁴ n¹² × 4t³
= 4 n¹² t⁴⁺³
= 4 n¹² t⁷

d. (2x³) × 3(x²y²)³ × 5y⁴
= 2 x³ . 3 ×⁶ y⁶ . 5 y⁴
= 2 . 3 . 5 . x³ . x⁶ . y⁶ . y⁴
= 30 x³⁺⁶ y⁶⁺⁴
= 30 x⁹ y¹⁰

Soal nomor 5

a. 0,00000056 = 5,6 × 10⁻⁷

b. 2.500.000 = 2,5 × 10⁶

c. 0,98 = 9,8 × 10⁻¹

d. 10.000.000.000.000 = 1 × 10¹³

Baca juga: Kunci Jawaban Matematika Kelas 9 Halaman 55 56, Cara Hitung Notasi Ilmiah Bentuk Baku Secara Benar

Soal nomor 6

a. a. 12 × 2³
= 12 × 8
= 96
= 9,6 × 10