Kunci Jawaban Matematika Kelas 9 Halaman 30 31 32: Cara Hitung Pembangian Pada Perpangkatan
Kunci jawaban Matematika kelas 9 halaman 30 31 32 cara menghitung pembagian perpangkatan dengan benar dapat menjadi bahan koreksi wali dan guru.
Penulis: Muhammad Alvian Fakka
Editor: Miftah
f. 55/(52 x 53)
= 55-2+3=1
= 51
= 5
g. (27 x 67)/47
= 27 x 27 x 37 / 47
= (2.2)7 x 37/47
= 47-7 x 37
= 40 x 37
= 1 x 37
= 37
h. (67 x 33)/27
(2.3)7 x 33/27
= 27 x 37 x 33/27
= 27-7 x 37+3
= 20 x 310
= 1 x 310
= 310
i. (106 x 42)/(253 x 83)
= (2.5)6 x (22)2 / (52)3 x (23)3
= 26 x 56 x 24 / 56 x 29
= 26+4-9 x 56-6
= 21 x 50
= 2 x 1
= 2
j. (215 : 92)/(7/2)2
= 215/92 x (2/7)2
= (3.7)5/(32)2 x 22/72
= 35 x 75 x 22/ 34 x 72
= 35-4 x 75-2 x 22
= 31 x 73 x 2
= 3 x 22 x 73
Soal nomor 2
a. (-y)5/(-y)2
= (-y)5-2=3
= y3
b. (1/t)7/(1/t)3
= (1/t)7-3=4
= 1/t7/1/t3
= 1/t7 . t3/1
= t3/t7
= t
= 1/t4
c. 3m7/m3
= 3m7-3=4
= 3m4
d. 42y8/12y5
= 42/12 . y8/y5
= (7/2)y3
e. ((1/t)7 : (1/t)3) x ((1/t)3 : (1/t)2)
= 1/t7/1/t3 x 1/t3/1/t2
= 1/t7/1/t2
= 1/t^7 . t2/1
= t2/t7
= t-5
= 1/t5
f. 3w4/w2 x 5w3
= 3w2 x 5w3
= 15 w5
Soal nomor 3
a. (0,24 x 0,22) : 0,25
= (0,2)4+2-5 = 1
= (0,2)1
= 1/5